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Time difference= 2PM -12 noon =2 hours ATQ- 10t = 15(t-2) 10t = 15t-30 30 =5t t = 6 hours Distance= d = 10t = 10 ×6 =60 km Time to reach by 1 PM= t-1 6-1= 5 hours Speed = 60 km /5 hours= 12 km/h
3 5 7 25 8...
11, 9, 15, 41 ,157, 789
6 6 13 39 ? 226
...91 93 97 100 ? 113
9 49 251 ? 2999 5989
...3 4.5 6.75 10.125 15.1875 22.78125 ?
...83, 88, 86, 91, 89, ?
Direction: Which of the following will replace ‘?’ in the given question?
2, ‘?’, 46, 136, 311, 605, 1086
1,2, 5, ‘?’, 41, 122, 365
43 ? 45 39 47 37
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