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    Question

    John cycles at 10 km/h to reach his destination at 2 PM.

    If he travels at 15 km/h, he will reach at 12 noon itself. At what speed should he travel to reach the place at 1 PM?
    A 12 km/h Correct Answer Incorrect Answer
    B 8 km/h Correct Answer Incorrect Answer
    C 11 km/h Correct Answer Incorrect Answer
    D 14 km/h Correct Answer Incorrect Answer

    Solution

    Time difference= 2PM -12 noon =2 hours ATQ- 10t = 15(t-2) 10t = 15t-30 30 =5t ┬а t = 6 hours Distance= d = 10t = 10 ├Ч6 =60 km Time to reach by 1 PM= t-1 6-1= 5 hours Speed ┬а = 60 km /5 hours= 12 km/h

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