Sheetal’s speed= 40 km/hr. Time taken by Sheetal = 5 hrs. Distance = Speed × Time = 40 × 5 = 200 km. ∴ Distance covered by Hemlata = 200 km. Time taken by Hemalata = 4 hrs. ∴ Hemlata’s Speed = (Distance )/Time = (200 )/4 = 50 km/hr. Sheetal’s increased speed= 50 km/hr. ∴ Time taken by Sheetal = (200 )/50 = 4 hrs. Hemlata’s increased speed = 60 km/hr. ∴ Time taken by Hemlata = (200 )/60 = 3(1/3) = 3hrs 20 minutes. ∴ Required difference = 4 hrs – 3hrs 20 minutes = 40 minutes.
________Function key refreshes the current window.
The key F12 opens a ___________________
A high speed memory device used in CPU for temporary storage during processing is called
The bubbles in a bubble memory pack are created with the help of
Which are the input devices that enable direct data entry into a computer system from source documents?
The portion of the operating system that resides in memory is known as:
A Personal Computer uses a number of chips mounted on a circuit board called
Which of the Following is not a non-impact printer?
From the set of candidate keys after selecting one of the keys as primary key, all other remaining keys are known as.
A key-board has at least:
