Question
1322 metres long train crosses a man who is moving in
the same direction with a certain speed, in 40 seconds. If the same train can cross a tree in 20 seconds with the same speed, then find the speed of the man.Solution
Speed of train = 1322/20 = 66.1 m/sec Let the speed of the man be āsā m/sec Relative speed of the train = (66.1 ā s) m/sec According to the question, (66.1 ā s) = 1322/40 Or, s = 66.1 ā 33.05 = 33.05 Therefore, speed of the man = 33.05Ā m/sec
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II. Partial efficiency measure
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