Let the original length of the train = x m ∴ Speed of the original train = x/20 m/s ∴ Length of the shorter train = x-200 ∴ speed of the shorter train = (x-200)/10 m/s Since, both the train are same their speed are also same ∴ (x )/20 = (x-200)/10 ⟹ 10 x = 20 x- 4,000 10 x =4,000 x = 400 ∴ Speed = x/20 =400/20 = 20m/s
43 ? 45 39 47 37
...6 6 13 39 ? 226
...If 2 4 6 x 14 28 30
Then, x³+ 2 x+1 = ?
20, 36, 103, 406, ?, 12130
200, 50, ‘?’, 46.875, 82.03125
14 26 50 98 194 ?
...What will be the next number in the series?
2,5,11,23,47,?
52 25 27 ? 208 1648
...52 26 39 97.5 ?
...Three series are given below. You have to find the values of P, Q and R, then establish a relationship among them.
I: 840, P , 584, 456,...
