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    Question

    Ajay and Vishal left the place тАШXтАЩ with different

    speeds which are in the ratio 4:3 respectively. Ajay left the place 36 seconds after Vishal. If after 72 seconds of the departure of Vishal, Ajay is 80 meters apart from Vishal, then find the speed of Vishal.
    A 16 km/hr Correct Answer Incorrect Answer
    B 12 km/hr Correct Answer Incorrect Answer
    C 15 km/hr Correct Answer Incorrect Answer
    D 20 km/hr Correct Answer Incorrect Answer
    E 18 km/hr Correct Answer Incorrect Answer

    Solution

    Let the speeds of Ajay and Vishal be 4x and 3x km/hr respectively. Distance covered by Vishal in 72 seconds = 3x x (5/18) x 72 = 60x m Distance covered by Ajay in 36 seconds = 4x x (5/18) x 36 = 40x m According to the question, => 60x тАУ 40x = 80 => x = 4 Therefore the speed of Vishal = 3x = 12 km/hr

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