Question
In a 15 km race, X, Y, and Z are running at uniform speed.
If ‘X’ beats ‘Y’ by 3 km, and ‘Y’ beats ‘Z’ by 2 km, then by how many metres does ‘X’ beat ‘Z’?Solution
ATQ,
When ‘X’ covers 15 km, ‘Y’ will cover 12 km
Similarly, when ‘Y’ covers 15 km, ‘Z’ covers 13 km
Therefore, when ‘Y’ covers 12 km, then ‘Z’ will cover = (12 × 13) / 15 = 10.4 km
Therefore, ‘X’ will beat ‘Z’ by = 15 – 10.4 = 4.6 km = 4600 metres
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
17% of 250 + ? = 108
32 + 26 × (484 ÷ 44) + 450 ÷ 9 = ?
40 × 5 + 27) × 9 = ?
What will come in the place of question mark (?) in the given expression?
193...
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
What will come in the place of question mark (?) in the given expression?
√1296 + (2/3 of 45% of 480) = ?
- Determine the value of ‘p’ if p = √529 + √1444
120% of 250 + 110 + 135 ÷ 5 = ?