A train has to cover a distance of 240 km in 20 hours. If it covers half journey in 3/5th time, then the speed of covering the remaining distance in the time left has to be:
Speed = Distance/time = 240/20 = 12 km/hr According to the question, New time = 3/5 x 20 = 12 hrs New distance = 1/2 x 240 = 120 km Required speed = Distance left/Time left = 120/8 = 15 km/hr
25% of 140 + 2 × 8 = ? + 9 × 5
?2 × 25 = 42 × 21 + 172
?% of 320 - 69 = 123
18 × 15 + 86 – 58 =? + 38
3.3 Times 2/27 of 40% of 364=?
(25)² × 4 ÷ 5 + (3)³ + 48=? + 425
4368 + 2158 – 596 - ? = 3421 + 1262
`(450 -: ?)/(2.5 xx 1.2)` = 250
(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)
Solve the following:
523 + 523 x 523 ÷ 523
