Question
A train has to cover a distance of 270 km in 15 hours.
If it covers half journey in 3/9th time, then the speed of covering the remaining distance in the time left has to be:Solution
Speed = Distance/time = 270/15 = 18 km/hr According to the question, New time = 3/9 x 15 = 5 hrs New distance = 1/2 x 270 = 135 km Required speed = Distance left/Time left = 135/10 = 13.5 km/hr
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