Question
The speed of the stream is 10 km/h. Boat ‘A’ covers
110 km distance against the stream in 11 hours and boat ‘B’ covers 65 km distance against the stream in 2 hours. The speed of boat ‘B’ in still water is how much percent of the speed of boat ‘A’ in still water?Solution
Speed of boat ‘A’ upstream = 110/11 = 10 km/h Speed of boat ‘B’ upstream = 65/2 = 32.5 km/h Speed of the boat ‘A’ in still water = 10 + 10 = 20 km/h Speed of the boat ‘B’ in still water = 32.5 + 10 = 42.5 km/h Required percentage = (42.5/20) × 100 = 212.5%
More Simplification Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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