Question
An amount was invested at simple interest for 2 years.
If the rate had been 8% higher, the interest would have increased by Rs. 320. What is the principal amount?Solution
Let initial rate of interest be r% per annum.
Let the principal be Rs. P
According to question;
P × (r + 8)/100 × 2 – P × r/100 × 2 = 320
Or, P(r + 8) – Pr = 320 × 100/2 = 16000
Or, 8P = 16000
So, P = 16000/8 = Rs. 2000
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 38x + 352 = 0
Equation 2: y² - 38y + 312 = 0
Quantity I: The cash price of a notebook is Rs. 100 but is can also be purchased on 11 monthly equal instalments of Rs. 10 each. Find rate of S.I.?
...I. 3x6- 19x3+16=0
II. 9y4- 27y2+20=0
I. 14p2 – 135p + 81 = 0
II. 7q2 – 65q + 18 = 0
I. x2 – 39x + 360 = 0
II. y2 – 36y + 315 = 0
I. x² - 208 = 233
II. y² + 47 - 371 = 0
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 50x + 600 = 0
Equation 2: y² - 51y + 630 = 0
I. 5x² -14x + 8 = 0
II. 2y² + 17y + 36 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 13x² - 60x + 47 = 0
Equation 2: 17y² - 80y + 63 = 0
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