Question
Raju invested a certain sum at
25% p.a. compound interest, compounded annually, and earned an interest of Rs. 2925 in 2 years. What will be the interest when the same amount is invested at 20% p.a. simple interest for three years?Solution
ATQ,
Compound Interest Formula: A = P × (1 + R/100)^T Given: Interest earned = Rs. 2925 Rate = 25% p.a. Time = 2 years A = P × 1.5625 Interest earned = A - P = 2925, P × 0.5625 = 2925 P = 2925 / 0.5625 P = 5200 Simple Interest Formula: SI = (P × R × T) / 100 Given: Principal = Rs. 5200 Rate = 20% p.a. Time = 3 years SI = (5200 × 20 × 3) / 100 SI = 3120 Hence, The interest earned with 20% p.a. simple interest for 3 years is Rs. 3120.
If x² + 2x + 9 = (x – 2) (x – 3), then the resultant equation is:
What will be the product of smaller roots of both equations.Â
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
I. 27x6 - 152x3 + 125 = 0
II. 216y6 - 91y3 + 8 = 0
I. x2 – 9x + 18 = 0
II. y2 – 5y + 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
I. 117x² + 250x + 117 = 0
II. 54y² -123y + 65 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 92x + 73 = 0
Equation 2: 17y² - 76y + 59 = 0
I. x2 – 13x + 40 = 0
II. 2y2 – 15y + 13 = 0Â
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. x2 – ...
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