Question
When Rs.6400 funded at SI of 12% p.a for certain
years which gives an interest of Rs.3840. If Rs.5000 is invested at CI compounded annually of 10% p.a for 3 years less than the time for which Rs.6400 was funded. Find the compound interest earned on Rs.5000.Solution
ATQ, we can say that S.I = ((P x R x T)/100) 3840 = 6400 x 12/100 x T T = 5 years Rs.6400 is invested for 2 years at 10% p.a. CI. Required interest = Rs 1050
342 – 232 + 256 – 104 = ?
14 × 11 + 25 – ? = 21% of 300
2850 ÷ 2.5 - ? × 42 = 300
What will come in the place of question mark (?) in the given expression?
(72 × 6 ÷ 12) × 6 = ?
Find the value of 325 × 5 + 31 × 21 – 22 × (63 − 52).
√? = 80% of 720 - 22% of 2500
5555 ÷ 11 ÷ 5 = 100 + ?
- What will come in place of (?) in the given expression.
[45 + (36 ÷ 6)] × 2 – 10 = ? (23.95)2 – (25.006)2 + (8.0099)2 – (7.07)2 = ? - (14.990)2
If a³ - b³ = (a - b)(a² + ab + b²), find a³ - b³ when a = 10 and b = 4.