Question
A person 'P' invested Rs. 'a' in
a simple interest (SI) SIP 'X' for 3 years at an annual interest rate of 10%. They also invested Rs. (a + 100) in a compound interest (CI) SIP 'Y', with a quarterly compounding rate of 40% per annum, for a period of 1 year. The interest earned from SIP 'X' is Rs. 358.2 less than the interest earned from SIP 'Y'. Determine the value of 'a'.Solution
ATQ, Given, CI – SI = 358.2 {(a+100) × [1 + (40/4)/100] - (a+100)} - (a × 10 × 3/100) = 358.2 {(a+100) × 110/100 × 110/100 × 110/100 × 110/100 - (a+100)} - (a × 3 × (10/100)) = 358.2 (a+100) × [121 -100 ]/100 - (30a/100) =358.2 (a+100) × (4641) - 3000a = 3582000 4641a - 3000a + 464100 = 3582000 1641a = 3582000 - 464100 a = (3117900/1641) = 1900
The income of Surya is Rs. 75,000. He spent 16(2/3)% of his income on food, 60% of the remaining income on rent and saved 44% of the income remaining a...
In a triangle ABC, AB = AC. The length of the median from A to BC is 9 cm and the angle between the median and AB is 60°. Find the length of AB.
HCF and LCM of two numbers are 13 and 455. If one number lies between 60 and 70, then the other number lies between
(32) -3/5 = ?
? = 49.99² ÷ (1.98⁵ + 8.01 × 89.91) + 75.15% of (263.89 × 49.11)
The sum of the ages of a father and his son is 50 years. After 5 years, the father's age will be twice that of his son. What are their present ages?
A regular hexagon has a side length of 6 units. What is the area of the hexagon?
Let a plane pass through the point (1, –1, 2) and is perpendicular to the vector 2i + j − 2k. Then its Cartesian equation is:
Solve: 2(x+3) = 8(x–1)
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