Question
Soni gets a SI of Rs. 3360 on a certain principle at the
rate of 7%p.a. in 2 years. What CI will she get on twice the principal in 2 years at the same rate?Solution
P= (SI ×100)/ (R × T) = (3360 × 100)/ (7 × 2) = 24000 Now the principle for CI=24000×2=48000 Count 3 years interest rate at the rate of 7% -7/100. 1st year100107 2nd year100107 1000011449 Rate increase =1449/10000) ×100=14.4% So now CI =48000×14.49/100 =6955.2
I. p² - 365 = 364
II. q - √ 529 = √ 169
If (5√P - 7√Q) = 5, [1.5P = 4Q-(R/3)+9] and (√P/√Q) = 1.6, then find out the value of ‘R’.
The equations 6x + my + 18 = 0 and 9x + 21y + 27 = 0 have a unique solution. Which of the following statements is definitely true?
I. p2 – 5p + 6 = 0
II. 36q2 = 81
...Find the value of 'a' and 'b' which satisfy the following equations:
9a + 7b = 30
4a - 5b = 62
The ratio of roots of the equation mx2 + nx + n = 0 is α/ β = a/b, then find the value of `sqrt(a/b)+sqrt(b/a)+sqrt(n/m)`
The slope of the equation 24x+ 8y =56 is
I. 8/(√x) + 6/(√x) = √x
II. y ³- (14)7/2 /(√y) = 0
The length of a line segment A, B is 10 units. The coordinates of point A are(2,3) and the value of ordinate of point B is 5. Then find the value of abs...
Find the area between the lines 18x +12y = 108, 9x + 6y = 27, x - axis and y -axis.
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