Question
Hemant invested Rs. βyβ at the rate of (r+2)% per
annum on simple interest and after four years Rs. 27520 was obtained as an interest. If Rs. (y+2500) was invested at the rate of βrβ% per annum compounded annually and after two years Rs. 16560 was obtained as an interest, then find out the value of βrβ.Solution
Hemant invested Rs. βyβ at the rate of (r+2)% per annum on simple interest and after four years Rs. 27520 was obtained as an interest.
y x (r+2)% x 4 = 27520
y x (r+2) x 4 = 2752000
y x (r+2) = 688000
y = 688000/(r+2)Β Β Eq.(i)
If Rs. (y+2500) was invested at the rate of βrβ% per annum compounded annually and after two years Rs. 16560 was obtained as an interest.
(y+2500)[{(100+r)/100}^2 - 1] = 16560Β
Put Eq.(i) in the above equation.
(688000/(r+2)+2500)[{(100+r)/100}^2 - 1] = 16560Β
5r^3+2386r^2β54000rβ662400=0
(rβ30) (5r^2+2536r+22080)=0
There are three values of βrβ. But two of them are negative and not possible.
So the value of βrβ = 30.
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