Question
Rs. ’P’ invested at a rate of 10% p.a. compound
interest (compounded annually) amounts to Rs. 7744 at the end of 2 years. Find the simple interest earned at the end of 4 years if the same amount is invested at the same rate.Solution
According to question; 1.10 × 1.10 × P = 7744 Or, P = Rs. 6400 Desired interest = 0.1 × 4 × 6400 = Rs. 2560
Statement: M>T≤Z; T>Q ; X ≥R>Q
I. X ≥ M
II. Q < M
Statements: Â P * R, M & N, R $ M
Conclusions:Â Â Â Â Â a) P @ MÂ Â Â Â Â Â Â Â Â Â Â Â Â b) P $ M
...In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and the...
Statement: B > C = J; B > S > E; B < N
Conclusion: I. E < C      II. J ≤ E
Statements:Â Â Â Â Â Â Â X @ Y % M % N; M $ P $ Z
Conclusions :     I. Y % Z               II. X @ N          �...
Statements: V ≤ R ≥ Q; R ≤ N < Y; I > Y ≤ S
Conclusions:
I. V ≤ S
II. I > Q
III. S > N
Statements: R % B, B & T, T @ E, E % G
Conclusions : I. T $ R II. R @ E III. B @ G
...Statement: H > G = M > S ; GÂ `>=` Â T > L; MÂ `<=` Â F <Â U
    Conclusion:  I. L > M          II. G < U
...How many such pairs of letter are there in the word TELEPHONE, each of which has as many letters between them in the word as in the English alphabet?
Statements: B > C; D > E = F < G ≥ H; C > I = D
Conclusions:
I. B < E
II. G > E
III. I < B
Relevant for Exams:
