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R + S = 120
70 + S = 120
S = 120 – 70 = 50.
Possible Runs of U will between 50 and 70.
The runs of Q is more than the runs of T. The number of persons more than Q is one less than the number of persons less than T.
Q > ___ > _____ > ___ T > ___ ……… (I)
____ > Q > ___ > T > ___ > ___ ……… (II)
The runs of R is more than U, whose runs is more than S. At least two persons have less runs than S.
Q > R > U > S > T > P ……… (I)
____ > Q > ___ > T > ___ > ___ ……… (II)
Case 2 will get discarded.
Therefore, the final arrangement is as follow:
Q(highest) > R > U > S > T > P(lowest)
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