Let the principal be P. ∴ P + CI for 3 yrs = Rs. 8,000 ----- (i) And P + CI for 2 yrs = Rs. 6,400 ----- (ii) Subtracting (ii) from (i), we get CI for the 3rd yr = 8,000 – 6,400 = Rs. 1600 Thus, CI calculated in the 3rd yr is basically the interest on the amount generated after 2 yrs which is Rs. 6,400. ∴ R = `(SIxx100)/(PxxT)` = `(1600xx100)/(6400xx1)` [if gte msEquation 12]>
(12% of 1250 + 85% of 400) x 10 = ?2
What will come in the place of question mark (?) in the given expression?
(70 × 8 ÷ 10) × 5 = ?
82.3 × 644.7 × 723.4 × 815.85 = 72?
The value of (40 + 3/4 of 32) /[37 + 3/4 of (34-6)] is:
236.23 - 653.23 + 696.23 = ?
7.4 × 8.2 + 3.5 × 4.5 = ? + 11.5 × 2.5
800 + 900 X (3)-2 - ? = 25 X 60 ÷ 2
808 ÷ (128)1/7 + 482 = 4 × ? + 846
30% of 215 + 135% of ? = 469.5