Let, rate of interest be ‘r’% per annum So, 1290 = 4000 × {(1 + r/100)2 – 1} 129/400 = {(1 + r/100)2 – 1} 529/400 = (1 + r/100)2 (23/20)2 = (1 + r/100)2 23/20 = 1 + r/100 3/20 = r/100, r = 15 So, simple interest earned = 4450 × 0.15 × 2 = Rs. 1335 Required amount = 1335 – 1290 = Rs. 45
The angle of depression of two ships from the top of a light house are 45º and 30º. if the ships are 120m on the opposite sides of li...
Simplify: sin (A + B) sin (A - B)
cot 4˚ x cot 47˚ x cot 42.3˚ x cot 43˚ x cot 47.7˚ x cot 86˚= ?
If 2y . cos θ - x . sin θ = 0 and 2x . sec θ - y . cosec θ = 3, what is the value of x² + 4y²?
From a point 50 meters away from the base of a tower, the angle of elevation of the top of the tower is 30°. Find the height of the tower.
If x = r sin A cos B, y = r sin A sin B and z = r cos A, then find x² + y² + z².
What is the value of [tan2 (90 – θ) – sin2 (90 – θ)] cosec2 (90 – θ) cot2 (90 – θ)?
...If 2sin y + cos y = √3 sin y, then find the value of tan y
