Divide Rs 2,760 in to two parts such that when these are invested for 2 and 4 years, respectively, at the rate of 5% per annum simple interest, the amounts received are equal. What is the second part (in Rs) invested?
Let for the 1st part it is Rs. x So, 2nd part = Rs. (2760 - x) According to the question, x + [(x × 2 × 5)/100] = (2760 - x) + [{(2760 - x) × 4 × 5}/100] ⇒ (100x + 10x)/100 = (276000 - 100x + 55200 - 20x)/100 ⇒ 110x = 331200 - 120x ⇒ 230x = 331200 ⇒ x = 331200/230 ⇒ x = 1440 So, 1st part = Rs. 1440 So, 2nd part = 2760 - 1440 ⇒ Rs. 1320 ∴ The second part (in Rs.) invested is 1320.
I. y/16 = 4/y
II. x3= (2 ÷ 50) × (2500 ÷ 50) × 42× (192 ÷ 12)
I. 2 x ² + x – 1 = 0
II. 2 y ² - 3 y + 1 = 0
...I. 96x² + 52x - 63 = 0
II. 77y² + 155y + 72 = 0
The quadratic equation (p + 1)x 2 - 8(p + 1)x + 8(p + 16) = 0 (where p ≠ -1) has equal roots. find the value of p.
I. x2 = 10
II. y2 - 9y + 20 = 0
...I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
I. 117x² + 250x + 117 = 0
II. 54y² -123y + 65 = 0
I. 2x2 + 12x + 18 = 0
II. 3y2 + 13y + 12 = 0
If 4x = 40, 3y = 33, what is the value of 6x + 4y?
I. 8x – 3y = 85
II. 4x – 5y = 67