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An amount of Rs. (y-2800) was invested on simple interest at the rate of (R+1)% per annum for 6 years. Interest after 6 years = (y-2800)x(R+1)%x6 Eq.(i) An another amount of Rs. (y+3200) was invested on simple interest at the rate of (R-2)% per annum for 5 years. Interest after 5 years = (y+3200)x(R-2)%x5 Eq.(ii) The interest obtained in both of the cases is the same. So Eq.(i) = Eq.(ii) (y-2800)x(R+1)%x6 = (y+3200)x(R-2)%x5 (i) 14800, 12 (14800-2800)x(12+1)%x6 = (14800+3200)x(12-2)%x5 12000x13%x6 = 18000x10%x5 9360 ≠ 9000 So these are not the correct values. (ii) 15800, 16 (15800-2800)x(16+1)%x6 = (15800+3200)x(16-2)%x5 13000x17%x6 = 19000x14%x5 13260 ≠ 13300 So these are not the correct values. (iii) 14800, 14 (14800-2800)x(14+1)%x6 = (14800+3200)x(14-2)%x5 12000x15%x6 = 18000x12%x5 10800 = 10800 So these are the correct values. (iv) 12800, 18 (12800-2800)x(18+1)%x6 = (12800+3200)x(18-2)%x5 10000x19%x6 = 16000x16%x5 11400 = 12800 So these are not the correct values.
√(195.99 X 8.99 X 15.87) X ³√124.99 = ? X 11.99
149.98% of 199.91 + 49.98% of 312.01 = (? - 26.01 + 65.99) × 5.98
24.11% of 249.99 + √143.97 ÷ 12.02 = ?
(64.99% of 599.91 + 49.99% of 199.99 + 135.11) = ?2
(0.89 3 + 1.64 3 +2.76 3 ) ÷ 5.89 = ?
30.11% of 149.99 + √195.97 ÷ 7.02 = ?
1080.04 – 330.18 + 449.98 ÷ 15.06 = ?
22.11 × 4.98 + 23.03 × 5.12 – 32.95 + 96.9 × 5.02 =?
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?