Question
A man borrowed Rs 300 and promised to pay back in 11
equal instalments of Rs 30 each. Find the rate of simple interest per annum?Solution
First month = Rs 300 Second month = Rs 270 Third month =Rs 240 Sum = (n )/2{2a +( n – 1 )d] a = 300 d = - 30 ⇒ 11/2 [2 × 300 + (11 – 1) (-30)] ⇒ 11/2 [600 – 300] ⇒ 11/2 × 300 = 1650 P = (300 ×11)/2 = 1,650 (P ×R ×T)/100 = S.I (1650 ×R ×1)/(100 ×12) = 30 R = (12 × 20)/11 = 240/11 %
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