Question
Three series I, II and III, are given below, which
contain a missing term 'P', 'Q' and 'R' respectively. Series I: 12, 13, 17, 44, P, 3425 Series II: 12.8, 32, 80, 200, 500, Q Series III: 15, 40, R, 170, 291, 460 Find the value of (Q - 4P + 6R).Β ΒSolution
Series I: 12 + 1ΒΉ = 13 13 + 2Β² = 17 17 + 3Β³ = 44 44 + 4β΄ = 300 300 + 5β΅ = 3425 'P' = 300 Series II: 12.8 Γ 2.5 = 32 32 Γ 2.5 = 80 80 Γ 2.5 = 200 200 Γ 2.5 = 500 500 Γ 2.5 = 1250 'Q' = 1250 Series III: 15 + 5Β² = 40 40 + 7Β² = 89 89 + 9Β² = 170 170 + 11Β² = 291 291 + 13Β² = 460 'R' = 89 Required value = 1250 - 4 Γ 300 + 6 Γ 89 = 1250 - 1200 + 534 = 584
- Out of his monthly income of Rs. 40000, Mohan spent Rs. 10000 less than he saved. What percentage of his income did he spend?
The ratio of three numbers is 3:8:10. If the difference between (smallest + largest) and (smallest + second largest) is 14, then find the largest number.
- 28% of 50% of 600 = p + 18, find the sum of the squares of the digits of βpβ.
βZβ is a two digit number in which the unit place digit is βPβ and the tens place digit is βQβ. The value of βPβ is smaller than the val...
The sum of a positive number 'A' and its square is 90. Find the value of (A2 - 7A).
In a yard, there are some rabbits and some parrots, only. If the total number of heads counted is 34 and total number of feet counted is 94, then find ...
If two numbers add up to 12 and the sum of their cubes is 1728, then what is the product of the two numbers?
- 'k' is the fraction which must be subtracted from (5/6) to get (2/9). Find the remainder when denominator of 'k' is divided by numerator of 'k'.
Find the smallest 3-digit number which when divided by 6, 8 and 9 leaves the same remainder 3 in each case.
Determine the sum of the first 16 odd numbers.