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      Question

      Given below are three numbers series I, II and II where

      each series contains a wrong (odd one out) term. The wrong number in series I, II and III are 'P', 'Q' and 'R', respectively. Find the values of 'P', 'Q' and 'R' and answer the questions that follow. I: 137, 112, 334, 279, 791, 710 II: 56, 90, 132, 180, 240, 306, 380 III: 226, 220, 244, 124, 884, -4192 The number that should actually come in place of 'P' is 'M'. Find the value of (M - R).
      A 4550 Correct Answer Incorrect Answer
      B 4960 Correct Answer Incorrect Answer
      C 4420 Correct Answer Incorrect Answer
      D 4780 Correct Answer Incorrect Answer
      E 4520 Correct Answer Incorrect Answer

      Solution

      For series I: 137 - 52 = 112 112 + 63 = 328 328 - 72 = 279 279 + 83 = 791 791 - 92 = 710 Therefore, 328 should come in place of 334. So, P = 334 For series II: 7 x 8 = 56 9 x 10 = 90 11 x 12 = 132 13 x 14 = 182 15 x 16 = 240 17 x 18 = 306 19 x 20 = 380 Therefore, 182 should come in place of 180. So, Q = 180 For series III: 226 - 3! = 220 220 + 4! = 244 244 - 5! = 124 124 + 6! = 844 844 - 7! = - 4196 Therefore, -4196 should come in place of - 4192. So, R = - 4192 M = 318 So, M - R = 328 - (-4192) = 328 + 4192 = 4520  

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