Question
Given below are two numbers series 'I' and 'II' where
the missing number in series I and II are 'P' and 'Q', respectively. Which among the given options gives the sum of 'P' and 'Q'? I: 40, 64, P , 412, 1242, 2754 II: 120, 150, 108, 164, 94, QSolution
For series I: 40 + 2³ × 3 = 64 64 + 3³ × 4 = 172 172 + 4³ × 5 = 492 492 + 5³ × 6 = 1242 1242 + 6³ × 7 = 2754 So, P = 172 For series II: 120 + 5 × 6 = 150 150 - 6 × 7 = 108 108 + 7 × 8 = 164 164 - 8 × 9 = 92 92 + 9 × 10 = 182 So, Q = 182 So, P + Q = 172 + 182 = 354
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