Answer-Three series (I, II and III) are given below. Each series contain one odd one out (wrong term) . Wro...

Series I consecutive prime numbers X consecutive natural numbers 374 11 x 2 396 396 13 x 3 435 435 17 x 4 503 503 19 x 5 598 598 23 x 6 736 374 should come in place of 370 So, P 370 Series II 279 102 12 279 101 380 380 82 32 380 73 453 453 62 52 453 61 514 514 42 72 514 65 579 579 22 92 579 85 664 514 should come in place of 510 So, R 510 Series III 5940 4 1485 1485 4.5 330 330 5 66 66 5.5 12 12 6 2 66 should come in place of 60 So, Q 60 R - P Q - 32 x P - 250 Q x P - 7R 510 - 370 60 - 32 x 370 - 250 60 x 370 - 7 x 510 140 28 x 120 60 x 370 - 3,570 5 x 120 60 x 370 - 3,570 600 60 x 370 - 3,570 10 x 370 - 3,570 3,700 - 3,570 130

Question

Three series (I, II and II

I are given below. Each series contain one odd one out (wrong term) . Wrong term in series I, III and II is denoted by 'P', 'Q' and 'R' respectively. Series I: 370, 396, 435, 503, 598, 736 Series II: 279, 380, 453, 510, 579, 664 Series III: 5940, 1485, 330, 60, 12, 2 Simplify the following expression: [(R -
P ÷ (Q - 32) x (P - 250) ] ÷ Q x P - 7R