Question
Find the pattern of the series and answer the question given below. Series: 16X, 48000, 16000, 4000, Y, 133(1/3) Find the value of (X/2) – 2.5Y.
16X × (1/2) = 48000 16X = 96000 X = 6000 4000 × (1/5) = Y 800 = Y Required value = (X/ 3) − 1.5Y = (6000/2) − 2.5(800) = 3000 – 2000 = 1000More Series Questions
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