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      Question

      There are three series given below which are following

      with the same pattern. Series I: 9, 10, 32, 163, 1145 Series II: 4, B, C, D, E Series III: F, G, H, I, J Also, G = 3C + 5, Find the product of F & H.
      A 9150 Correct Answer Incorrect Answer
      B 9050 Correct Answer Incorrect Answer
      C 9250 Correct Answer Incorrect Answer
      D 9450 Correct Answer Incorrect Answer
      E 9350 Correct Answer Incorrect Answer

      Solution

      Series I: 9 ├Ч 1 + 1 = 10 10 ├Ч 3 + 2 = 32 32 ├Ч 5 + 3 = 163 163 ├Ч 7 + 4 = 1145 Series II: 4 ├Ч 1 + 1 = 5 (B) 5 ├Ч 3 + 2 = 17 (C) 17 ├Ч 5 + 3 = 88 (D) 88 ├Ч 7 + 4 = 620 (E) Series III: F ├Ч 1 + 1 = G G ├Ч 3 + 2 = H H ├Ч 5 + 3 = I I ├Ч 7 + 4 = J And, G = 3C + 5 G = (3 ├Ч 17) + 5 G = 56 Now we can find the value of F, F ├Ч 1 + 1 = G F ├Ч 1 + 1 = 56 F = 55 Also, we can find the value of H, G ├Ч 3 + 2 = H 56 ├Ч 3 + 2 = H H = 170 The product of F & H = (55 ├Ч 170) = 9350

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