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    Question

    Below given are 2 wrong number series. Series I:

    19, 30, 6, 45, – 11, 67 Series II: 141, 148, 223, 398, 723, 1248 I. The absolute difference between the incorrect numbers is divisible by 37. II. The sum of the incorrect numbers is divisible by 13. III. When 'x' is divided by 'y', the remainder is 15, where 'x' represents the correct replacement for the wrong term in series I, and 'y' represents the correct replacement for the wrong term in series II.
    A Only I and III Correct Answer Incorrect Answer
    B Only II Correct Answer Incorrect Answer
    C Only I and II Correct Answer Incorrect Answer
    D Only III Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ, Series 1 19 + 11 × 1 = 30 30 – 12 × 2 = 6 6 + 13 × 3 = 45 45 – 14 × 4 = – 11 – 11 + 15 × 5 = 64 x = 64 Series 2 {148 – 123 = 25} 75 – 25 = 50 {223 – 148 = 75} 175 – 75 = 100 {398– 223 = 175} 325 – 175 = 150 {723 – 398 = 325} 525 – 325 = 200 1248 – 723 = 525 y = 123 I.141 – 67 = 74 = 2 × 37 (True) II.141 + 67 = 208 = 208/13 = 16 (True) III.64/123 = (False) Hence, Only I and II

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