Question
Given below are two number series I and II where each series has a wrong (odd one out) number. The number that will actually come in place of the wrong number in series I and II are 'P' and 'Q' respectively. Find which among the given options gives the correct sum of 'P' and 'Q'. I: -20, -57, -68, -53, -10, 49 II: 30, 55, 120, 240, 436, 725
More Series Questions
- Given below are three numbers series I, II and II where each series contains a wrong (odd one out) term. The wrong number in series I, II and III are 'P', ...
- 19.11 × 5.98 + 20.03 × 3.12 – 34.95 + 97.9 × 3.02 =?
- 20 60 180 540 ? 4860
- 34, 18, 20, ?, 70, 180
- Find the pattern of the series and answer the question given below. Series: 16X, 48000, 16000, 4000, Y, 133(1/3) Find the value of (X/2) – 2.5Y.
- 12 78 385 ? 4629 9260
- 64 48 36 22 16 8
- If 7 43 x 1311 5247 15739 Then, x - x/2 + 2 = ?
- 6 6 13 39 ? 226
- 30 27 20 9 ? - 25
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Think You're Ready for RBI Grade B?
RBI Grade B 2026 Phase 1 Memory Based Paper
- 200 Questions with Detailed Solutions
- Section-wise Coverage (GA, English, Quant & Reasoning)
So, -12 should come in place of -10 So, P = -12 For series II: 30 + 52 = 55 55 + 82 = 119 119 + 112 = 240 240 + 142 = 436 436 + 172 = 725 Therefore, 119 should come in place of 120. So, Q = 119 Sum of P and Q = 119 + (-12) = 107