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ATQ,
Let the original number of left-handed and right-handed students be ‘5x’ and ‘6x’, respectively.
ATQ;
(5x + 10) / (6x + 10) = (15/16)
Or, 16 × (5x + 10) = 15 × (6x + 10)
Or, 80x + 160 = 90x + 150
Or, 10x = 10
Or, x = 1
So, the number of right-handed students originally = 6 × 1 = 6
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