Question
Find the mean proportion of 7.2 and 16.2.
Solution
ATQ,
Mean proportion of 'a' and 'b' = √ab
So, required mean proportion = √(7.2 X 16.2)
= √(6 X 1.2 X 6 X 2.7)
= 6 X √(1.2 X 2.7)
= 6 X √(3 X 0.4 X 3 X 0.9)
= 6 X 3 X √(0.4 X 0.9)
= 6 X 3 X √(0.36)
= 6 X 3 X 0.6
= 10.8
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