Question
The cost of diamond varies directly as the square of its
weight. A diamond broke into four pieces with weights in the ratio 1 : 4 : 5 : 6. if the loss in the total value of the diamond was Rs. 89,000. The price of the original diamond was?Solution
Let the weight of the pieces of diamond be x, 4x, 5x, 6x Total weight of diamond = x + 4x + 5x + 6x = 16x Price = k(weight) 2 where, K is constant Original price = k(16x) 2 Price of pieces = (kx 2 + 16kx 2 + 25kx 2 + 36kx 2 ) = 78kx 2 Loss in price = 256kx 2 - 78kx 2 = 178kx 2 which is given as 89,000 = 178kx 2 = 89000 = kx 2 = 500 Original price = 256kx 2 = 256 x 500 = 128000
13 19 32 52 ? 113
1290, 1225, 1175, ?, 1112, 1095, 1085
? , 864, 432, 144, 36, 7.2
106, 124, 88, 142, ?, 160
What value should come in the place of (?) in the following number series?
5670, 1620, 540, 216, 108, ?
7, 9, 21, ?, 107, 197
71, 79, 88, 152, ?, 393
14, 20, 29, 44, 65, ?
What will come in place of the question mark (?) in the following series?
2.5, 6.5, 18.5, 54.5, 162.5, 486.5, ?
22, 37, 63, 98, 148, ?
