Question
The ratio of two numbers 'a' and 'b' is 6:2,
respectively. Whereas the ratio of 'b' and 'c' is 10:11, respectively. When 14 is added to 'a', it becomes four times of 'b'. Find the sum of 'a', 'b' and 'c'.Solution
ATQ, let the numbers 'a' and 'b' be '6k' and 2k respectively. So, 'c' = 2k X (11/10) = '2.2k' ATQ; (6k + 14) = 4 X (2k) Or, 6k + 14 = 8k Or, k = 7 So, required sum = 6k + 2k + 2.2k = 10.2 X 7 = 71.4
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