Question
If, ‘x’ varies directly as ‘y’, and when x = 56, y
= 28, then find the value of ‘x’, when ‘y’ = 40.Solution
ATQ,
x ∝ y
So, Let, x = k × y (where, ‘k’ is a proportionality constant)
ATQ,
56 = k × 28
So, k = (56 / 28) = 2
So, when ‘y’ = 40, then,
x = 2 × 40 = 80
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