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    Question

    'A' and 'B' have coins in the ratio of 7:5, respectively.

    If 'B' gives 2 coins to 'A', then the new ratio of coins with 'A' and 'B' becomes 3:2, respectively. Find the initial difference between coins with 'A' and 'B'.
    A 20 Correct Answer Incorrect Answer
    B 16 Correct Answer Incorrect Answer
    C 12 Correct Answer Incorrect Answer
    D 10 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the initial number of coins that 'A' and 'B' have be 7x and 5x , respectively.
    After giving 2 coins to 'A', the number of coins with 'A' and 'B' will be: (7x+2) and (5x-2)
    ATQ;
    {7x + 2}/{5x – 2} = {3/2}
    Or, 2(7x + 2) = 3(5x – 2)
    Or, 14x+4 = 15x-6
    Or, x=10
    The initial difference between coins with 'A' and 'B':
    7x – 5x = 2x = 20

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