Question
Three numbers βLβ, βMβ and βNβ are such
that βLβ is five times of βMβ and βNβ is equal to the average of βLβ and βMβ. If the sum of these three numbers is 540, then find the difference between the largest and smallest number.Solution
Let the value of βMβ be β2xβ So, value of βLβ = 5 Γ 2x = β10xβ So, value of βNβ = (10x + 2x)/2 = 12x/2 = β6xβ ATQ; 10x + 2x + 6x = 540 Or, 18x = 540 Or, x = 30 So, the difference (L - M) = 10x - 2x = 8x = 8 Γ 30 = 240
Choose the next number in the series.
25, 41, 73, 89, 121,?
Select the option that represents the letters that, when sequentially placed from left to right in the blanks below, will complete the letter series.
Select the figure from the options that can replace the question mark (?) and logically complete the series.
Which figure should replace the question mark (?) if the following series were to be continued?
Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series.
CDG_ IJ_Z O_SZ _VYZ _BEZ
Which two numbers should be interchanged to make the given equation correct?
(99 β 42 + 11) + (36 Γ· 6) Γ 7 β 50 = 73
(NOTE: Numbers ...
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Arguments:
I. Β Yes, this will save the precious life of human beings...
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