Question
Three numbers βLβ, βMβ and βNβ are such
that βLβ is five times of βMβ and βNβ is equal to the average of βLβ and βMβ. If the sum of these three numbers is 540, then find the difference between the largest and smallest number.Solution
Let the value of βMβ be β2xβ So, value of βLβ = 5 Γ 2x = β10xβ So, value of βNβ = (10x + 2x)/2 = 12x/2 = β6xβ ATQ; 10x + 2x + 6x = 540 Or, 18x = 540 Or, x = 30 So, the difference (L - M) = 10x - 2x = 8x = 8 Γ 30 = 240
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