Question
Find the fourth proportion of (k + 2), (2k), and (3k +
6). (Note: 'k' is the smallest two-digit prime number.)Solution
k = 11
k + 2 = 13
2k = 22
3k + 6 = 33 + 6 = 39
13 : 22 :: 39 : m
13m = 22 × 39 = 858
m = 858 ÷ 13 = 66
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