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    Question

    If 'a' is the mean proportion of 12.8 and 0.8 and 'b' is

    the third proportional to 1.2 and 4.8, then find (a + b) :(b - a) .
    A 5:4 Correct Answer Incorrect Answer
    B 3:5 Correct Answer Incorrect Answer
    C 7:5 Correct Answer Incorrect Answer
    D 6:5 Correct Answer Incorrect Answer

    Solution

    Mean proportion of two numbers 'p' and 'q' is โˆš(p X q) .

    So, 'a' = โˆš(12.8 X 0.8)

    Or, 'a' = โˆš10.24 = 3.2

    Third proportional to two numbers 'p' and 'q' is (q2/p) .

    So, 'b' = (4.82/1.2)

    Or, 'b' = (23.04/1.2) = 19.2

    Required ratio = (3.2 + 19.2) :(19.2 - 3.2) = 22.4:16 = 7:5

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