Question
‘x’ varies directly as ‘y’. If at x = 24 the
value of ‘y’ is 25% more than ‘x’, then find the value of ‘x’ when ‘y’ = 55.Solution
ATQ; X = k × y (Where ‘k’ is proportionality constant) ATQ; 24 = k × (1.25 × 24) Or, k = (4/5) So, required value = (4/5) × 55 = 44
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