Question
βxβ varies directly as βyβ. If at x = 24 the
value of βyβ is 25% more than βxβ, then find the value of βxβ when βyβ = 55.Solution
ATQ; X = k Γ y (Where βkβ is proportionality constant) ATQ; 24 = k Γ (1.25 Γ 24) Or, k = (4/5) So, required value = (4/5) Γ 55 = 44
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
17% of 250 + ? = 108
32 + 26 Γ (484 Γ· 44) + 450 Γ· 9 = ?Β
40 Γ 5 + 27) Γ 9 = ?
What will come in the place of question mark (?) in the given expression?
193...
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
What will come in the place of question mark (?) in the given expression?
β1296 + (2/3 of 45% of 480) = ?
- Determine the value of βpβ if p = β529 + β1444
120% of 250 + 110 + 135 Γ· 5 = ?