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Let the total amount of mixture be x liters. Initially, the ratio of milk to water is 7:5, so the amount of milk = (7/12) × x, and the amount of water = (5/12) × x. After 60 liters of mixture is removed, the amount of milk and water removed will be in the same ratio of 7:5. Milk removed = (7/12) × 60 = 35 liters. Water removed = (5/12) × 60 = 25 liters. Now, 60 liters of water is added, so the new amount of milk is (7/12)x - 35, and the new amount of water is (5/12)x - 25 + 60. The new ratio of milk to water is 3:4. So, (7/12)x - 35 / [(5/12)x - 25 + 60] = 3/4. Cross-multiply: 4[(7/12)x - 35] = 3[(5/12)x - 25 + 60] 4(7x - 420) = 3(5x + 420) 28x - 1680 = 15x + 1260 28x - 15x = 1680 + 1260 13x = 2940 x = 2940 / 13 liters Now, calculate the amount of milk: Milk = (7/12) × 2940/13 ≈ 132 liters Correct option: e
What will come in the place of question mark (?) in the given expression?
(70 × 8 ÷ 10) × 5 = ?
20% of 1500 – 75% of 200 = 125% of ?
?2 = √20.25 × 10 + √16 + 32
[192 ÷ 6 × 5] ÷ (? + 3) = 20
65% of ? = 50 + 20 × 4
What will come in place of the question mark (?) in the following question?
24.30% of 372.32 = ?
40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?
{(300 ÷ 15)% of 1500} ÷ 6 = ? + 120
(√ 1444 ÷ 5) × 3.25 = ?