Question
The cost of diamond varies directly as the square of its
weight. A diamond broke into four pieces with weights in the ratio 2 : 3 : 4 : 5. if the loss in the total value of the diamond was Rs. 142,000. The price of the original diamond was?Solution
Let the weight of the pieces of diamond be 2x, 3x, 4x, 5x Total weight of diamond = 2x + 3x + 4x + 5x = 14x Price ∝ (weight)2 => Price = k(weight)2 ; where, K is constant Original price = k(14x)2 Price of pieces = (4kx2 + 9kx2 + 16kx2 + 25kx2) = 54kx2 Loss in price = 196kx2 – 54kx2 = 142kx2 which is given as 142,000 => 142kx2 = 142000 => kx2 = 1000 Original price = 196kx2 = 196 x 1000 = 196000
14, 17, 23, 32, ?, 59
32, 64, 8, ?, 2, 4
9 19 39 ? 159 319
18 29 16 31 ? 33
13, 29, 65, 129, ?, 373
47, 72, 122, ?, 297, 422
What will come in place of the question mark (?) in the following series?
24, 8, 15, ?, 12, 4
12, 18, 30, 54, ?, 198
What will come in place of the question mark (?) in the following series?
9, 22, 61, ?, 217, 334
4, 7, 12, 21, 36, ?
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