Question
If A : B = 8:5 and A is 21 more than B then find the sum
of A and B.Solution
Let x be the common multiplier. Then, => A : B = 8x : 5x => A = B + 21 => 8x = 5x + 21 => x = 7 A + B = 8x + 5x = 13x = 13 × 7 = 91
Statements: E $ N, N * G, H % E
Conclusions: a) G # H Â Â Â b) H $ N
Statements: C % K, K @ L, L & U, U $ G
Conclusions: I.G @ L II. C @ L III. C @ G
...Statements: L ≥ R, U ≤ N, N < M > I
Conclusion:
I. R > I
II. M ≥ U
Statements: L ≥ F = Z < P, Q ≥ A > C = P
Conclusions:
I. A > F
II. Q > Z
Statements:
M > N = W; J < P = N; Y > P
Conclusions:
I. Y > W
II. M < Y
III. J > M
Statements: C $ O, O% D, A © D
Conclusions:Â
I. A © OÂ
II. D @ CÂ
III. C © A
Statement: E < F ≤ G = H, I ≥ G ≤ J ≤ K
Conclusion: I. K > E Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. H > K
...Statements: T > U, V > W, U = X, R ≥ X, V = R
Conclusion:
I. T ≥ W
II. W > T
Statements: Â P > Q > R > S > T < U < V < W < X
Conclusion:
I. Â P > T
II. Â U < X
...Statements: S > P = N ≥ G; Y = G ≥ J < O
Conclusions:
I. P ≥ J
II. J < P