Question
Find the value of {(3125)(n/5) × 5(2n
+ 1)}/ {25n × 5(n - 1)} ÂSolution
{(3125)(n/5) × 5(2n + 1)}/ {25n × 5(n - 1)}  = 5(n + 2n + 1) / 5(2n + n - 1) = 5(3n + 1)/5(3n - 1) = 5(3n + 1 - 3n + 1) = 52  = 25   Â
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