Question
The weights (in kg) of 11 students are: 40, 45,
47, 50, 52, 52, 55, 55, 55, 60, 65 Find: (a) the mean weight, (b) the median weight,Solution
Total = 40 + 45 + 47 + 50 + 52 + 52 + 55 + 55 + 55 + 60 + 65 Compute stepwise: 40+45=85 85+47=132 132+50=182 182+52=234 234+52=286 286+55=341 341+55=396 396+55=451 451+60=511 511+65=576 Total = 576 (a) Mean = 576 / 11 β 52.36 kg (b) Median: Middle term (6th value) as data is sorted and n = 11: Median = 6th value = 52 kg
Simplify the following expressions and choose the correct option.
{[(13)Β² β (7)Β²] Γ· 12} Γ 4 = ?
(25)Β² Γ 4 Γ· 5 + (3)Β³ + 48=? + 425
?2 + 114 - 48 Γ· 2 Γ 5 = 163
182 + 10 Γ 12 - ? = 312
2/5 of 3/4 of 7/9 of 7200 = ?
If (3 Γ 144 β 252 Γ· 14) Γ· 18 = β1024 β x, then find the value of βxβ.
12.50% of 1440 - 17 × 51 + 721 =?
[(15)³ × (8)²] ÷ (90 × 6) = ?²
?2 - (40% of 240) = 25 X 5
Simplify: 48 Γ· 4 Γ 3 + 5 Γ (6 β 2)