Question
The weights (in kg) of 11 students are: 40, 45,
47, 50, 52, 52, 55, 55, 55, 60, 65 Find: (a) the mean weight, (b) the median weight,Solution
Total = 40 + 45 + 47 + 50 + 52 + 52 + 55 + 55 + 55 + 60 + 65 Compute stepwise: 40+45=85 85+47=132 132+50=182 182+52=234 234+52=286 286+55=341 341+55=396 396+55=451 451+60=511 511+65=576 Total = 576 (a) Mean = 576 / 11 ≈ 52.36 kg (b) Median: Middle term (6th value) as data is sorted and n = 11: Median = 6th value = 52 kg
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If Â
 = 4 then 
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If x + 1/x = 5, then x2 + 1/x2 is:
(x – 6) 2 + (y + 2) 2 + (z – 4) 2 = 0, then find the value of 4x - 3y + z.
22% of ‘x’ is equal to 66% of ‘y’, then find the value of x: y.
