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    Question

    Solve the inequality: (3x тАУ 4)/(x + 2) >

    1
    A x < тАУ2 or x > 3 Correct Answer Incorrect Answer
    B x < 2 or x > -3 Correct Answer Incorrect Answer
    C x < тАУ4 or x > 5 Correct Answer Incorrect Answer
    D x < тАУ2 or x > -3 Correct Answer Incorrect Answer

    Solution

    ATQ,

    (3x тАУ 4)/(x + 2) тАУ 1 > 0 [(3x тАУ 4) тАУ (x + 2)]/(x + 2) > 0 (2x тАУ 6)/(x + 2) > 0 2(x тАУ 3)/(x + 2) > 0 Critical points: тАУ2, 3 Sign analysis тЖТ positive in (тАУтИЮ, тАУ2) and (3, тИЮ) Hence┬а x < тАУ2 or x > 3

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