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Start learning 50% faster. Sign in nowLet the quantity of each alloy be 1 unit. For the first alloy, copper = 3/5 and zinc = 2/5 For the second alloy, copper = 5/8 and zinc = 3/8 Now, in the new alloy, copper = (1 × 3/5 + 1 × 5/8) / 2 = (24 + 25) / 40 = 49/40 Zinc = (1 × 2/5 + 1 × 3/8) / 2 = (16 + 15) / 40 = 31/40 The ratio of copper to zinc in the new alloy = 49:31 Correct answer: d
(33 + 6.25% of 4096) = ? + 2 × 119
(1520 - 1350) ÷ (550 – 500) = ?
25 × 5 - ?% of 150 = 102 - 2
(√7225 x √1225)/(√625) = ?
√361 ÷ (21/23) × 84 = ?
32% of 450 + 60% of 150 = ? × 9
5/2 of 5/6 of 12/5 of 54 % of 5250 = ?
(560 ÷ 32) × (720 ÷ 48) = ?
136% of 560 - 2/7 of 630 + 45% of 420 =?