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To find the second derivative of y = tan⁻¹x at x = 1. y = tan⁻¹x dy/dx = 1/(1 + x²) d²y/dx² = -2x/(1 + x²)² At x = 1: d²y/dx² = -2(1)/(1 + 1)² = -2/4 = -1/2
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