Question
'O' is the incentre of △ABC. Given that ∠ABC = 64°
and ∠BCA = 96°, determine the measure of ∠BOC.Solution
∠OBC= (1/2) X ∠ABC (since BO is the angle bisector of ∠ABC)
∠OBC =(1/2) of 64o = 32o
And ∠OCB = (1/2) X ∠ACB = (1/2) X 96o = 48o
In rOBC,
∠BOC = 180o - (32o + 48o) = 100o
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