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    Question

    If 'x' is a positive integer such that x + 1/x┬а= 2,

    then find the value of┬а (x3 + x2 тИТ 2x тАУ 6)/(4x4 + 2x2).
    A -3 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 1 Correct Answer Incorrect Answer
    D -1 Correct Answer Incorrect Answer

    Solution

    x +┬а1/x ┬а= 2 Or, x2┬а+ 1 = 2x Or, x2┬а- 2x + 1 = 0 Or, (x - 1)2┬а= 0 So, 'x' = 1 (x3 + x2 тИТ 2x тАУ 6)/(4x4 + 2x2) = (13 + 12 тАУ 2 X 1 тАУ 6)/(4 X 14 + 2 x 12) = - 6/6 = - 1

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